The figure shows pressure versus density graph for an ideal gas at two temperature $T_{1}$ and $T_{2}$ :

$T_{1} > T_{2}$

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$T_{1} = T_{2}$

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$T_{1} < T_{2}$

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None of these

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Solution

The correct option is A
$T_{1} > T_{2}$

Ideal gas equation

PV = nRT

$P V = \frac{x}{M} R T$

$P M = ρ R T$

Slope $= t a n \propto \frac{P}{ρ}$

$θ_{2} > θ_{1}$

$t a n θ_{2} > t a n θ_{1}$

$T_{1} > T_{2}$

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Similar questions

The figure shows graphs of pressure versus density for an ideal gas at two temperature $T_{1} a n d T_{2}$ which is correct?

T_{1}

T_{2}

T_{1}

T_{2}

T_{1}

T_{2}

T_{1}

T_{2}

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