The figure shows pressure versus density graph for an ideal gas at two temperatures $T_{1}$ and $T_{2}$

T_{1}

T_{2}

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T_{1}

T_{2}

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T_{1}

T_{2}

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Nothing can be predicted

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Solution

The correct option is A $T_{1}$ > $T_{2}$
${(\frac{d P}{d ρ})}_{T_{1}} > {(\frac{d P}{d ρ})}_{T_{2}}$
This means, the curve for $T_{1}$ is more steeper than that of $T_{2}$
$∴ T_{1} > T_{2}$

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Similar questions

The figure shows pressure versus density graph for an ideal gas at two temperature $T_{1}$ and $T_{2}$ :

T_{1}

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The figure shows graphs of pressure versus density for an ideal gas at two temperature $T_{1} a n d T_{2}$ which is correct?

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