The final product obtained by distilling ethyl alcohol with the excess of chlorine and $C a (O H)_{2}$ is

C H_{3} C H O

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C C l_{3} C H O

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C H C l_{3}

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(C H_{3})_{2} O

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Solution

The correct option is C $C H C l_{3}$
When chlorine reacts with ethyl alcohol in the presence of KOH, chloroform is obtained as a final product.
the product is $C H C l_{3}$
Hence C is corret option

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Similar questions

C a O C l_{2} + H_{2} O \to C a (O H)_{2} + X

X + C H_{3} C H O \to Y

Y + C a (O H)_{2} \to C H C l_{3}

Y

C a {(O H)}_{2}

K O H