The first and last term of an ap are 1 and 11 if the sum of its terms is 36 then a = ______,d=_____,n=_____&an=_________
Let a be the 1st term, and l be the last term.
Let Sn be the sum of n terms of an AP
Given -
a = 1
l = 11
Sn = 36
The formula for the sum of n terms of an AP, when the 1st term and the last term of the AP is given, is
Sn = n/2 (a + l)
Applying this formula:
36 = n/2 (1 + 11)
=> 72 = 12n
=> n = 72/12 = 6
Given First term = 1 therefore a = 1
Last Term = 11 Therefore an = 11
6th Term is 11,
Therefore a6 = a +(6-1)d
11 = 1 + 5d
=> d = 2