Question

The first I.P. of sodium is numerically equal to the:

• A. second I.P. of $Mg$
• B. electron affinity of $Ne$
• C. electron affinity of $N{a}^{+}$
• D. first I.P. of $Mg$

Answer 1

The correct option is C electron affinity of $N{a}^{+}$

The first I.P of sodium is numerically equal to the Electron affinity of $N{a}^{+}$. It is because ionization energy is energy to remove electron. Electron affinity is released by the addition of electron.