The first term of an AP is $- 50$ and the $50 t h$ term is $48$ . Find the common difference

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Solution

The correct option is D $2$
Given,
First term $a = - 50$

$50^{t h}$ term, $T_{50} = 48$

$d = ?$

$T_{n} = a + (n - 1) d$

$T_{50} = 48$

$48 = - 50 + (50 - 1) d$

$48 = - 50 + 49 d$

$49 d = 98$

$d = 2$

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