The number of terms in an AP is 10. The $n^{t h}$ term of this AP is 50 and the common difference is 2. Find the first term.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
32

$t_{n} = a + (n - 1) d$

where,

' $a$ ' is the first term,

'd' is the common difference,

'n' is the no. of terms,

' $t_{n}$ ' is the $n^{t h}$ term.

Given, $t_{n}$ = 50, n = 10

d = 2
Substituting these values in the equation, we get,

$50 = a + (10 - 1) 2$

$\Rightarrow$ 50 = a+ $9 \times 2$

$\Rightarrow$ 50 = a+18

$\Rightarrow$ a = 32

Suggest Corrections

Similar questions

Q. In an AP the first term is 8, nth term is 33 and the sum to n terms is 123. Find the number of terms and common difference.

In an AP, where the first term is 7 and the common difference is 4, ___ term of the AP will be five times the first term.
Represent this situation in the form of an equation, where $a$ = first term, $a_{n}$ = $n^{t h}$ term and $d$ is the common difference.