The first three members of the paraffin series are ${C H}_{4}, C_{2} H_{6}$ and $C_{3} H_{8}$ . The next higher homologue of this series will be :

C_{4} H_{3}

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C_{2} H_{7}

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C_{4} H_{6}

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C_{4} H_{10}

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Solution

The correct option is D $C_{4} H_{10}$
$C H_{4}$ , $C_{2} H_{6}$ and $C_{3} H_{8}$ are all alkanes with the general formula; $C_{n} H_{2 n + 2}$ , where $n = 1, 2, 3, 4....$ .etc. Therefore the formula of the next higher homologue where $n = 4$ is; $C_{4} H_{10}$ .

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Similar questions

C H_{4}

C_{2} H_{6}

C_{3} H_{8}

C_{4} H_{10}

(C_{9} H_{8} O_{4})

(C_{7} H_{6} O_{3})

(C_{4} H_{6} O_{3})

C_{7} H_{6} O_{3} + C_{4} H_{6} O_{3} \to C_{9} H_{8} O_{4} + C_{2} H_{4} O_{2}

C_{4} H_{10}

{^{404} C}_{4} - {^{4} C}_{1} {^{303} C}_{4} + {^{4} C}_{2} {^{202} C}_{4} - {^{4} C}_{3} {^{101} C}_{4}

y = C_{1} + C_{2} e^{x} + C_{3} e^{- 2 x + C_{4}}

C_{1}, C_{2}, C_{3}, C_{4}

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