The first three terms of $A . P$ are $(3 y - 1)$ . $(3 y + 5)$ and $(5 y + 1)$ . Then $y$ equals to _____.

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Solution

Given that,

The first $3$ terms of A.P. are $(3 y - 1), (3 y + 5), (5 y + 1)$ .

Therefore,

$2 (3 y + 5) = 3 y - 1 + 5 y + 1$

$6 y + 10 = 8 y$

$2 y = 10$

$y = 5$

Hence, the value of $y$ is $5$ .

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