Question

The fish caught by Neetu was of weight
$3\frac{3}{4}$ kg and the fish caught by Narendra was of weight $2\frac{1}{2}$ kg. How much more did Neetu's fish weigh than that of Narendra's fish?

• A. $\frac{5}{4}Kg$
• B. $\frac{3}{4}Kg$
• C. $\frac{1}{4}Kg$
• D. $\frac{5}{2}Kg$

Answer 1

The correct option is A $\frac{5}{4}Kg$

Given, the weight of fish caught by Neetu = $3\frac{3}{4}Kg$
The weight of fish caught by Narendra = $2\frac{1}{2}Kg$
We can express a mixed fraction interms of an improper fraction as,

$\frac{(\text{Whole}\times \text{Denominator})\text{+ Numerator}}{\text{Denominator}}$

So, the weight of fish caught by Neetu
$=3\frac{3}{4}=\frac{(3\times 4)+3}{4}=\frac{15}{4}$
And the weight of the fish caught by Narendra $=2\frac{1}{2}=\frac{(2\times 2)+1}{2}=\frac{5}{2}$

Difference between the weights of Neetu's fish and Narendra's fish
= difference between $\frac{15}{4}$ and $\frac{5}{2}$
= $\frac{15}{4}-\frac{5}{2}$

$\frac{15}{4}$ and $\frac{5}{2}$ are unlike fractions. So let's convert them into like fractions. The LCM of the denominator of the fractions $\frac{15}{4}$ and $\frac{5}{2}$ i.e. the LCM of 4 and 2 is 4.
Now, write the equivalent fractions of $\frac{15}{4}$ and $\frac{5}{2}$ having denominator 4.

$\frac{15}{4}=\frac{15\times 1}{4\times 1}=\frac{15}{4}and\frac{5}{2}=\frac{5\times 2}{2\times 2}=\frac{10}{4}$
Difference between the weights of Neetu's fish and Narendra's fish
$=\frac{15}{4}-\frac{10}{4}=\frac{15-10}{4}=\frac{5}{4}$
So, Neetu's fish weighed $\frac{5}{4}$ kg more than that of Narendra's fish.