Question

The flash of a gun is seen by man $3$ seconds before the sound is heard. Calculate the approximate distance of the gun from the man (the speed of sound in air is $332m/sec$ ).

Answer 1

Step 1: Given data

Speed of sound $=332\frac{m}{sec}$

If the time of seeing the flash $=tsec$

Then, time of hearing sound$=t+3sec$

Step 2: We know

$Speed=\frac{Dis\tan ce}{Time}$

so, $dis\tan cetravelledbylight=speedoflight\times time$

$dis\tan cetravelledbylight=3\times {10}^8\times t---\left(1\right)$

similar way, $dis\tan cetravelledbysound=332(t+3)---\left(2\right)$

Step 3: $Dis\tan cetravelledbylight=Dis\tan cetravelledbysound$

$3\times {10}^8\times t=332\times (t+3)$

When we solve the equation then we get

$t=332\times {10}^{-8}sec---\left(3\right)$

Step 4: We put the value of $t$ in the equation $\left(1\right)$

$Dis\tan ceofgunfromtheman=3\times {10}^8\times 332\times {10}^{-8}m$

$Dis\tan ceofgunfromtheman=996m$

Hence, the approximate distance of the gun from the man is $996m$