Question

The floor of a building consists of around $3000$ tiles which are rhombus shaped and each of its diagonals are $45cm$ and $30cm$ in length. Find the total cost of flooring if each tile costs rupees $20per{m}^2$

Answer 1

Let $d_1=45cm$ and $d_2=30cm$ be the two diagonals of the rhombus respectively.

Area of each tile = $\frac{d_1\times d_2}{2}=\frac{45\times 30}{2}=675{cm}^2$

Area of 3000 tiles = $300\times 675=2025000{cm}^2=202.5m^2$

Cost of flooring = $Rs.(202.5\times 20)=Rs.4050$