Question

The following data gives the amount of manure (in thousand tonnes) manufactured by a company during some years:

Year	1992	1993	1994	1995	1996	1997
Manure (in thousand tonnes)	15	35	45	30	40	20

(i) Represent the above data with the help of a bar graph.
(ii) Indicate with the help of the bar graph the year in which the amount of manure manufactured by the company was maximum.
(iii) Choose the correct alternative:

The consecutive years during which there was maximum decrease in manure production are
(a) 1994 and 1995
(b) 1992 and 1993
(c) 1996 and 1997
(d) 1995 and 1996

Answer 1

Let's draw two mutually perpendicular lines OX and OY.
Along the horizontal line OX, lets mark the years; and along the vertical line OY, let's mark the amount of manure in tonnes.
Along the axis OX, let's choose an equal width of each bar, keeping the gap between the bars the same.
We will now choose a suitable scale to determine the heights of the bars.
Here, let's consider 1 big division = 5 thousand tonnes of manure
Therefore, the heights of the various bars are as follows:
Height of the bar against the year 1992 $=\frac{15}{5}=3$ units.
Height of the bar against the year 1993 $=\frac{35}{5}=7$ units.
Height of the bar against the year 1994 $=\frac{45}{5}=9$ units.
Height of the bar against the year 1995 $=\frac{30}{5}=6$ units.
Height of the bar against the year 1996 $=\frac{40}{5}=8$ units.
Height of the bar against the year 1997 $=\frac{20}{5}=4$ units.
Based on the above calculation, the bar graph is as follows:
(i)


(ii) The amount of manure manufactured in the year 1994 was the maximum.

(iii) (c) 1996 and 1997
Explanation: The production decreased by 15 thousand tonnes from the year 1994 to 1995, and from 1996 and 1997 the production of manure decreased by 20 thousand tonnes.