Question

The following data gives the number (in thousands) of applicants registered with an Employment Exchange during. 1995-2000:

Year	1995	1996	1997	1998	1999	2000
Number of applicants registered (in thousands)	18	20	24	28	30	34

Construct a bar graph to represent the above data.

Answer 1

Let's draw two mutually perpendicular lines OX and OY.
Along the horizontal line OX, let's mark years; and along the vertical line OY, let's mark the number of applicants registered.
Along the axis OX, let's choose a suitable width for each bar, the gap between the bars being the same.
We will now choose a suitable scale to determine the heights of the bars.
Here, let's choose 1 big division = 4 thousand applicants
Therefore, the heights of the bars are as follow:
Height of the bar against the year 1995 $=\frac{18}{4}=4.5$ units.
Height of the bar against the year 1996 $=\frac{20}{4}=5$ units.
Height of the bar against the year 1997 $=\frac{24}{4}=6$ units.
Height of the bar against the year 1998 $=\frac{28}{4}=7$ units.
Height of the bar against the year 1999 $=\frac{30}{4}=7.5$ units.
Height of the bar against the year 2000 $=\frac{34}{4}=8.5$ units.
Based on the above calculation, the bar graph is as follows: