Question

The following table shows the interest paid by a company (in lakhs):

Year	1995-96	1996-97	1997-98	1998-99	1999-2000
Interest (in lakhs of rupees)	20	25	15	18	30

Draw the bar graph to represent the above information.

Answer 1

Let's draw two mutually perpendicular lines OX and OY.
Along the horizontal line OX, let's mark years; and along the vertical line OY, let's mark the amount of interest paid by the company.
Along the axis OX, let's choose a suitable width for each bar, keeping the gap between the bars the same.
We will now choose a suitable scale to determine the heights of the bars.
Here, let's consider 1 big division = 5 lakhs of rupees paid as interest by the company
Therefore, the heights of the various bars are as follows:
Height of the bar against the year 1995 − 96 $=\frac{20}{5}=4$ units.
Height of the bar against the year 1996 − 97 $=\frac{25}{5}=5$ units.
Height of the bar against the year 1997 − 98 $=\frac{15}{5}=3$ units.
Height of the bar against the year 1998 − 99 $=\frac{18}{5}=3.6$ units.
Height of the bar against the year 1999 − 2000 $=\frac{30}{5}=6$ units.
Based on the above calculation, the bar graph is as follows: