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Question

The following diagram shows a screw gauge when it is closed. What is its zero error? It is given that the least count is 0.01 mm.

A
-0.98 mm
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B
+0.98 mm
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C
-0.02 mm
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D
+0.02 mm
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Solution

The correct option is D +0.02 mm
As the zero of the head scale lies below the pitch scale axis, the zero error is positive. Reading of the screw guage is equal to the zero error.

Zero Error = MSR + (n × L.C)
where:
MSR: Main scale reading
n: Division of head scale
LC: Least count

Zero Error = 0 + (2 × 0.01 mm)
Zero Error = + 0.02 mm

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