The following diagram shows a screw gauge when it is closed. What is its zero error? It is given that the least count is 0.01 mm.
A
-0.98 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
+0.98 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
-0.02 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
+0.02 mm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D +0.02 mm As the zero of the head scale lies below the pitch scale axis, the zero error is positive. Reading of the screw guage is equal to the zero error.
Zero Error = MSR + (n × L.C) where: MSR: Main scale reading n: Division of head scale LC: Least count
Zero Error = 0 + (2 × 0.01 mm) Zero Error = + 0.02 mm