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Question

The following equilibrium constants were determined at 1120 K: 2CO(g)C(s)+CO2(g) Kp1=1014 atm1
CO(g)+Cl2(g)COCl2 Kp2=6×103 atm1
What is the equilibrium constant Kp for the following reaction at 1120 K. C(s)+CO2(g)+2Cl2(g)2COCl2(g)

A
36×104 atm1
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B
3.6×109 atm1
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C
3.6×105 atm1
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D
3.6×1010 atm1
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Solution

The correct option is B 3.6×109 atm1
2CO(g)C(s)+CO2(g); Kp1=1014 atm1......(1)
CO(g)+Cl2(g)COCl2(g); Kp2=6×103 atm1.....(2)
Multiply eqn (2) by (2), we get
2CO(g)+2Cl2(g)2COCl2(g) Kp2=(6×103)2 atm1 ...(3)
reverse eqn (1) we get
C(O)+CO2(g)2CO Kp11=11014atm1 ...(4)
add eqn (3) and (4)
C(s)+CO2(g)+2Cl2(g)2COCl2(g)
K=Kp12×Kp11
K=(6×103)2×11014
,K=36×1061014
K=36×108
K=3.6×109 atm1

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