The following equilibrium is established when hydrogen chloride is dissolved in acetic acid.
$H C l + C H_{3} C O O H ⇌ C H_{3} C O O H_{2}^{+} + C l^{-}$ .
The set that characterizes the conjugate acid-base pairs is:

(H C l, C H_{3} C O O H)

and

(C H_{3} C O O H_{2}^{+}, C l^{-})

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(H C l, C H_{3} C O O H_{2}^{+})

and

(C H_{3} C O O H, C l^{-})

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(C H_{3} C O O H_{2}^{+}, H C l)

and

(C l^{-}, C H_{3} C O O H)

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(H C l, C l^{-})

and

(C H_{3} C O O H_{2}^{+}, C H_{3} C O O H)

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Solution

The correct option is D $(H C l, C l^{-})$ and $(C H_{3} C O O H_{2}^{+}, C H_{3} C O O H)$
The conjugate base of an acid is formed when the acid donates a proton
$(H C l, C l^{-})$ and $(C H_{3} C O O H_{2}^{+}, C H_{3} C O O H)$

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Similar questions

H C l + C H_{3} C O O H \to C l^{-} + C H_{3} C O O H_{2}^{+}

H C l + {C H}_{3} C O O H ⇌ {C l}^{-} + {C H}_{3} C O O H_{2}^{+}

H C l

{C H}_{3} C O O H

{C H}_{3} C O O H + H C l ⇌ {C H}_{3} C O O H_{2}^{+} + {C l}^{-}

C H_{3} C O O H + H F ⇌ C H_{3} C O O H_{2}^{+} + F^{-}

{C H}_{3} C O O H + H F ⇌ {C H}_{3} C O O H_{2}^{+} + F^{-}

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