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Question

The following fig. shows I-V graph for a given metallic wire at two temperatures T1 and T2.Then,


A

Temperature T1 is more

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B

Temperature T2 is more

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C

T1 is same as T2

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D

None of the above

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Solution

The correct option is B

Temperature T2 is more


The slope of the graph = I/V

In case of T2, I/V is less. Hence, V/I (=R) is more.

Value of resistance increases with increasing temperature. Hence, T2 >T1.


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