The following fig- shows I-V graph for a given metallic wire at two temperatures T 1 and T 2- Then-A- Temperature T 1 is moreB- Temperature T 2 is moreC- T 1 is same as T 2D- None of the above

The correct option is B Temperature T2 is more The slope of the graph = I/V In case of T2, I/V is less. Hence, V/I (=R) is more. Value of resistance increases ...

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Standard XII

Physics

Ohm's Law in Scalar Form

The following...

Question

The following fig. shows I-V graph for a given metallic wire at two temperatures T₁ and T₂.Then,

Temperature T₁ is more

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Temperature T₂ is more

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T₁ is same as T₂

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None of the above

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Solution

The correct option is B
Temperature T₂ is more

The slope of the graph = I/V

In case of T₂, I/V is less. Hence, V/I (=R) is more.

Value of resistance increases with increasing temperature. Hence, T₂ >T₁.

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The following fig. shows I-V graph for a given metallic wire at two temperatures T1 and T2.Then,

The correct option is B Temperature T2 is more The slope of the graph = I/V In case of T2, I/V is less. Hence, V/I (=R) is more. Value of resistance increases with increasing temperature. Hence, T2 >T1.

The following fig. shows I-V graph for a given metallic wire at two temperatures T₁ and T₂.Then,

The correct option is B
Temperature T₂ is more

The slope of the graph = I/V

In case of T₂, I/V is less. Hence, V/I (=R) is more.

Value of resistance increases with increasing temperature. Hence, T₂ >T₁.