The following figure is a rectangle in which x : y = 4 : 6 , find the values of x and y
36°, 54°
Given that ABCD is a rectangle . All angles of a rectangle are 90°
∴ Consider triangle BCF
∠ BCF = 90°
∴ x + y = 90 ( sum of angles of a triangle is 180°)
Since x: y = 4:6 , Let the angles be 4k and 6k
we have 4k + 6k = 90°
10k = 90°
k = 9
Hence x = 4(9) = 36° and y = 6(9) = 54°