Question

The following figure shows a triangle ABC in which $DC=BC$and $\angle A>\angle ACD$ then $\angle B>2\angle A$
If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

Here angle CDB is exterior angle. and we know,

If one side of a triangle is extended, then the exterior angle is equal to the sum of the opposite interior angles.

So, $\angle A+\angle ACD=\angle CDB$

$\angle A>\angle ACD$

$2\ast \angle A>\angle CDB$ ...............eq 1

As DC=BC

so, $\angle B=\angle CDB$ ...............eq 2

from eq 1 and eq 2

$2\ast \angle A>\angle B$

Answer 0