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Question

The following graph shows the variation of ionization energies with the atomic number in the second period (Li−Ne). The value of ionization energy of Na will be:


A
Above Ne
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B
Below Ne but above O
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C
Below Li
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D
Between N and O
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Solution

The correct option is C Below Li
Li and Na are in the same group. Na is a 3rd period element and is bigger than Li. In Na, the distance between the nucleus and the outer most electron is greater than Li. Thus, the outer most electron is loosely bound with the nucleus and the removal of electrons is easier as compared to Li.

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