The value of x in the partial redox equation
$M n O_{4}^{-} + 8 H^{+} + x e = M n^{2 +} + 4 H_{2} O$ is

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Solution

The correct option is A
5

$M n O_{4}^{-} + 8 H^{+} + 5 e^{-} = M n^{+ +} + 4 H_{2} O$

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Similar questions

5 {F e}^{2 +} + M n O_{4}^{-} + 8 H^{+} ⇌ {M n}^{2 +} + 5 {F e}^{3 +} + 4 H_{2} O

{F e}^{3 +} + e^{-} ⟶ {F e}^{2 +}, {E_{1}}^{o}

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} ⟶ {M n}^{2 +} + 4 H_{2} O, {E_{2}}^{o}

n

M n O_{4}^{-} + 8 H^{+} + n e^{-} ⟶ M n^{2 +} + 4 H_{2} O

M n O_{4}^{-} + 8 H^{+} + x e^{-} ⟶ M n^{2 +} + 4 H_{2} O

M n O_{4}^{-} + 8 H^{+} + x e \to M n^{2 +} + 4 H_{2} O

M n O_{4}^{-} + 8 H^{+} + x e^{-} ⟶ M n^{2 +} + 4 H_{2} O

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