The following question contains two statements. Choose one of the options below:
Statement 1 : $[F e (H_{2} O)_{5} N O] S O_{4}$ is paramagnetic.
Statement 2 : The Fe in $[F e (H_{2} O)_{5} N O] S O_{4}$ has three unpaired electrons.

Statement-1 is True, Statement -2 is true, Statement - 2 is a correct explanation for Statement -1

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Statement -1 is True, Statement -2 is true, Statement-2 is not a correct explanation for Statement-1

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Statement-1 is True, Statement-2 is False

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Statement-1 is False, Statement-2 is True

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Solution

The correct option is A Statement-1 is True, Statement -2 is true, Statement - 2 is a correct explanation for Statement -1
Both the statements-1 and -2 are true. Fe is +1 oxidation state because NO is present as $N O^{+}$ . Electronic configuration of $F e^{+}$ is $[A r] 3 d^{6} 4 s^{1}$ . The electron present in the 4s orbital shifts to the 3d orbital giving rise to $3 d^{7}$ configuration. The ligands $H_{2} O$ and $N O^{+}$ are weak and cannot cause the pairing of 3d electrons
$F e^{+}$ : $[A r] 3 d^{7} 4 s^{0}$

It has three unpaired electrons.

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The following question contains two statements. Choose one of the options below: Statement 1 : [Fe(H2O)5NO]SO4 is paramagnetic. Statement 2 : The Fe in [Fe(H2O)5NO]SO4 has three unpaired electrons.

The following question contains two statements. Choose one of the options below:
Statement 1 : $[F e (H_{2} O)_{5} N O] S O_{4}$ is paramagnetic.
Statement 2 : The Fe in $[F e (H_{2} O)_{5} N O] S O_{4}$ has three unpaired electrons.