The foot of an elephant has an area of $275 {c m}^{2}$ . If the mass of elephant is $2200 k g$ , find the pressure exerted by the elephant on the ground, ( $g = 10 m$ $s^{- 2}$ ).

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Solution

Area = 275 ${c m}^{2} = 0.0275 m^{2} . (f o r o n e l o g)$
Force = 2200 kg $\times$ 10 = 22000N
Area of fourleg = 4 $\times$ 0.0275 $m^{2}$
Pressure = $\frac{F o r c e}{A r e a} = \frac{22000}{0.11} P_{a} = 2 \times 10^{5} P_{a}$

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The foot of an elephant has an area of 275cm2. If the mass of elephant is 2200kg, find the pressure exerted by the elephant on the ground, (g=10m s−2).

Area = 275cm2=0.0275m2.(foronelog)Force = 2200 kg × 10 = 22000NArea of fourleg = 4×0.0275m2Pressure = ForceArea=220000.11Pa=2×105Pa

The foot of an elephant has an area of $275 {c m}^{2}$ . If the mass of elephant is $2200 k g$ , find the pressure exerted by the elephant on the ground, ( $g = 10 m$ $s^{- 2}$ ).

Area = 275 ${c m}^{2} = 0.0275 m^{2} . (f o r o n e l o g)$
Force = 2200 kg $\times$ 10 = 22000N
Area of fourleg = 4 $\times$ 0.0275 $m^{2}$
Pressure = $\frac{F o r c e}{A r e a} = \frac{22000}{0.11} P_{a} = 2 \times 10^{5} P_{a}$