The force between two short dipoles separated by a distance r is directly proportional to ?

r^{2}

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r^{- 2}

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r^{- 3}

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r^{- 4}

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Solution

The correct option is D $r^{- 4}$
$F = p_{2} \frac{d E_{1}}{d r} = p_{2} \frac{d}{d r} [\frac{1}{4 π ϵ_{0}} \frac{2 p_{1}}{r^{3}}] F \propto \frac{1}{r^{4}}$

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The force between two short dipoles separated by a distance r is directly proportional to ?

The correct option is D r−4F=p2dE1dr=p2ddr[14πϵ02p1r3]F∝1r4

The correct option is D $r^{- 4}$
$F = p_{2} \frac{d E_{1}}{d r} = p_{2} \frac{d}{d r} [\frac{1}{4 π ϵ_{0}} \frac{2 p_{1}}{r^{3}}] F \propto \frac{1}{r^{4}}$