The formula of the complex compound is :

[C r C l (N O_{2}) (N H_{3})_{4}] N H_{3} \cdot C l

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[C r C l (N H_{3})_{5}] C l \cdot N O_{2}

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[C r (N O_{2}) (N H_{3})_{5}] C l_{2}

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[C r (N H_{3})_{5}] N O_{2} \cdot C l_{2}

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Solution

The correct option is B $[C r (N O_{2}) (N H_{3})_{5}] C l_{2}$
One molecule of this compound produces three ions in aqueous solution.
Out of this one ion is the complex cation and the other two ions are two chloride ions. This is confirmed when two moles of AgCl are obtained per mole of the complex by reaction with excess silver nitrate. Hence, two chloride ions must be outside of the coordination sphere.

Thus the formula of the complex compound is $[C r (N O_{2}) (N H_{3})_{5}] C l_{2}$ .

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