wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The fourth term in the expansion of (1−2x)32 will be


A

- 34x4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

x32

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

-x32

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

34x4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

x32


Expansion of (12x)32

= 1+32(2x)+32.12.12(2x)2+32.12(12)16(2x)3+.........

Hence 4th term is x32


flag
Suggest Corrections
thumbs-up
11
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Binomial Theorem for Any Index
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon