The fraction $\frac{2 (\sqrt{2} + \sqrt{6})}{3 (\sqrt{2 + \sqrt{3}})}$ is equal to _________

\frac{2 \sqrt{2}}{3}

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\frac{2 \sqrt{3}}{3}

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\frac{4}{3}

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Solution

The correct option is D $\frac{4}{3}$
answer is D) 4/3

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Similar questions

The fraction 2(√2 + √6)/3(√2+3) is equal to.

\frac{1}{1 \cdot 2} + \frac{1 \cdot 3}{1 \cdot 2 \cdot 3 \cdot 4} + \frac{1 \cdot 3 \cdot 5}{1 \cdot 2 \cdot 3 \cdot 4 \cdot 5 \cdot 6} + . . . . . . to \infty

\frac{1 + 4.343 + 7.4 + 2.3.49 + 7.343}{16 + 2^{6} . 3^{1} + 2^{5} . 3^{3} + 2^{6} . 3^{3} + 2^{4} . 3^{4}}

S c

\frac{1}{1 \cdot 2 \cdot 3} + \frac{1}{2 \cdot 3 \cdot 4} + \frac{1}{3 \cdot 4 \cdot 5} + \frac{1}{4 \cdot 5 \cdot 6}

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