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Byju's Answer
Standard XII
Chemistry
Entropy
The free ener...
Question
The free energy change for the following reactions are given below
C
2
H
2
(
g
)
+
5
2
O
2
(
g
)
⟶
2
C
O
2
(
g
)
+
H
2
O
(
l
)
;
△
G
0
=
1234
k
J
C
(
s
)
+
O
2
(
g
)
⟶
C
O
2
(
g
)
;
△
G
0
=
−
394
k
J
H
2
(
g
)
+
1
2
O
2
(
g
)
⟶
H
2
O
(
l
)
;
△
G
0
=
−
237
k
J
What is the standard free energy change for the reaction,
H
2
(
g
)
+
2
C
(
s
)
→
C
2
H
2
(
g
)
A
-209 kJ
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B
-2259 kJ
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C
+2259 kJ
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D
209 kJ
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Solution
The correct option is
D
209 kJ
Required equation
H
2
(
g
)
+
2
C
(
s
)
⟶
C
2
H
2
(
g
)
△
G
Reverse equation
1
Multiply equation
2
with
2
Now,
△
G
=
−
△
G
1
+
2
△
G
2
+
△
G
3
=
−
(
−
1234
)
+
2
×
(
−
394
)
+
(
−
237
)
=
+
209
K
J
Suggest Corrections
1
Similar questions
Q.
Given that :
2
C
(
s
)
+
2
O
2
(
g
)
→
2
C
O
2
(
g
)
;
Δ
H
=
−
787
kJ
H
2
(
g
)
+
1
/
2
O
2
(
g
)
→
H
2
O
(
l
)
;
Δ
H
=
−
286
kJ
C
2
H
2
(
g
)
+
5
2
O
2
(
g
)
→
2
C
O
2
(
g
)
+
H
2
O
(
l
)
;
Δ
H
=
−
1310
kJ.
Heat of formation of acetylene is:
Q.
For the two equations given below:
H
2
(
g
)
+
1
2
O
2
(
g
)
⟶
H
2
O
(
l
)
+
x
1
k
J
H
2
(
g
)
+
1
2
O
2
(
g
)
⟶
H
2
O
(
g
)
+
x
2
k
J
Select the correct answer.
Q.
Given that:
2
C
(
s
)
+
2
O
2
(
g
)
⟶
2
C
O
2
(
g
)
;
Δ
H
=
−
787
k
J
.
.
.
(
i
)
H
2
(
g
)
+
1
2
O
2
(
g
)
⟶
H
2
O
(
l
)
;
Δ
H
=
−
286
k
J
.
.
.
(
i
i
)
C
2
H
2
(
g
)
+
5
2
O
2
(
g
)
⟶
2
C
O
2
(
g
)
+
3
H
2
O
(
l
)
.
.
.
.
(
i
i
i
)
Δ
H
=
−
1301
k
J
Heat formation of acetylene is:
Q.
Consider the following reactions.
(a)
H
+
(
a
q
)
+
O
H
−
(
a
q
)
=
H
2
O
(
l
)
,
Δ
H
=
−
X
1
kJ
m
o
l
−
1
(b)
H
2
(
g
)
+
1
2
O
2
(
g
)
=
H
2
O
(
l
)
,
Δ
H
=
X
2
kJ
m
o
l
−
1
(c)
C
O
2
(
g
)
+
H
2
(
g
)
=
C
O
(
g
)
+
H
2
O
(
l
)
−
X
3
kJ
m
o
l
−
1
(d)
C
2
H
2
(
g
)
+
5
2
O
2
(
g
)
=
2
C
O
2
(
g
)
+
H
2
O
(
l
)
+
X
4
kJ
m
o
l
−
1
Enthalpy of formation of
H
2
O
(
l
)
is:
Q.
Calculate the heat of hydrogenation of
C
2
H
2
to
C
2
H
4
.
H
2
(
g
)
+
1
2
O
2
(
g
)
⟶
H
2
O
(
l
)
;
Δ
H
=
−
68.32
k
c
a
l
C
2
H
2
(
g
)
+
1
2
O
2
(
g
)
⟶
2
C
O
2
(
g
)
+
H
2
O
(
l
)
;
Δ
H
=
−
310.61
k
c
a
l
C
2
H
4
(
g
)
+
3
O
2
(
g
)
⟶
2
C
O
2
(
g
)
+
H
2
O
(
l
)
;
Δ
H
=
−
337.32
k
c
a
l
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