You visited us 1 times! Enjoying our articles? Unlock Full Access!

Van't Hoff Factor

The freezing ...

Question

The freezing point depression constant for water is $- {1.86}^{0} C m^{- 1} .$ If 5.00 g $N a_{2} S O_{4}$ is dissolved in 45.0 g $H_{2} O,$ the freezing point is changed by ${3.82}^{0} C .$
Calculate the vant Hoff factor for $N a_{2} S O_{4} .$

2.05

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.63

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.11

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.381

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2.63$
$K_{f} = - 186^{\circ} c m^{- 1}$
$Δ T_{r} = i \times K_{f} \times m$
$3.82 = i \times 1.86 \times \frac{5 \times 1000}{142 \times 45}$
$i = 2.63$

Hence, the correct option is $B$

Suggest Corrections

Similar questions

{1.86}^{o} c m^{- 1}

5.0

N a_{2} S O_{4}

45.0

H_{2} O

- {3.82}^{o} C

N a_{2} S O_{4}

{1.86}^{o} C

m^{- 1}

5

N a_{2} S O_{4}

H_{2} O

- {3.82}^{o} C

N a_{2} S O_{4}

5 g

N a_{2} S O_{4}

45 g

H_{2} O

{3.72}^{\circ} C

N a_{2} S O_{4}

{1.86}^{\circ} C k g m o l^{- 1}

0.0711

N a_{2} S O_{4}

- {0.320}^{o}

K_{f}

1.86

m o l^{- 1}

19.5 g

C H_{2} F C O O H

500 g

{1.00}^{0} C

Join BYJU'S Learning Program