The freezing point depression of 0-001 m Kx-FeCN6- is 7-44 - 10-3 K -Determine the value of x-Given-Kfwater - 1-86 K kg mol-1 Assume complete ionisation of Kx-FeCN6-

Given : Δ T_f =7.44 × 10^ 3 K Molality=10^ 3 m Since, Δ T_f = i × K_f × m 7.44 × 10^ 3 = i × 1.86 × 10^ 3 i = 4 Degree of dissociation (α) : α = i 1n 1 Als ...

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Standard XII

Chemistry

Van't Hoff Factor

The freezing ...

Question

The freezing point depression of $0.001 m K_{x} [F e (C N)_{6}]$ is $7.44 \times 10^{- 3} K$ .
Determine the value of x.
Given:
$(K_{f})_{w a t e r} = 1.86 K k g m o l^{- 1}$
Assume complete ionisation of $K_{x} [F e (C N)_{6}]$

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Solution

The correct option is C $3$
Given :
$Δ T_{f} = 7.44 \times 10^{- 3} K Molality = 10^{- 3} m$
Since,

$Δ T_{f} = i \times K_{f} \times m 7.44 \times 10^{- 3} = i \times 1.86 \times 10^{- 3} i = 4$

Degree of dissociation $(α)$ :
$α = \frac{i - 1}{n - 1}$
Also ,
$K_{x} [F e (C N)_{6}] \to x K^{+} + [F e (C N)_{6}]^{x -} n = (1 + x)$

Putting the values;

$1 = \frac{4 - 1}{(1 + x) - 1} x = 3$

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Similar questions

The freezing point depression of

10^{- 3}

molal aqueous solution of a compound

K_{x} [F e (C N)_{6}]

7.44 \times 10^{- 3}

K. Find

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Q. The freezing point depression of

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0.0744 K

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. If the solute undergoes complete dissociation, what is the correct molecular formula for the solute?

Q. The freezing point depression of a

1.00 \times 10^{- 3}

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Q. An aqueous solution freezes at 272.4 K while pure water freezes at 273 K. Determine the depression in freezing point of solution .

[Given :

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and vapour pressure of water at 298 K = 23.756 mm of Hg].

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Van't Hoff Factor

Standard XII Chemistry

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The freezing point depression of 0.001 m Kx[Fe(CN)6] is 7.44×10−3 K . Determine the value of x. Given: (Kf)water=1.86 K kg mol−1 Assume complete ionisation of Kx[Fe(CN)6]

The correct option is C 3Given : ΔTf=7.44×10−3 KMolality=10−3 m Since, ΔTf=i×Kf×m7.44×10−3=i×1.86×10−3i=4 Degree of dissociation (α) : α=i−1n−1 Also , Kx[Fe(CN)6]→xK++[Fe(CN)6]x−n=(1+x) Putting the values; 1=4−1(1+x)−1x=3

The freezing point depression of $0.001 m K_{x} [F e (C N)_{6}]$ is $7.44 \times 10^{- 3} K$ .
Determine the value of x.
Given:
$(K_{f})_{w a t e r} = 1.86 K k g m o l^{- 1}$
Assume complete ionisation of $K_{x} [F e (C N)_{6}]$