wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The freezing point of a 0.08 molal solution of NaHSO is 0.3720C. Calculate the dissociation constant for the reaction.
HSO4H+SO24
Kf for water = 1.86Km1.

Open in App
Solution

NaHSO4Na++HSO4
0.08 0.08
Tf=kfm

m=Tfkf=0.3721.86=0.2

HSO4H++SO42
At +=0 0.08 0 0
At eqb (0.08x) x x

(0.08x)+2x=0.2
x=0.04

k=[H+][SO42][HSO4]=(0.04)(0.04)(0.04)=0.04

Hence, the answer is 0.04.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Depression in Freezing Point
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon