The freezing point of equimolal aqueous solution will be highest for:

L a (N O_{3})_{3}

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C_{6} H_{12} O_{6}

(Glucose)

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C_{6} H_{5} N^{+} H_{3} C l^{-}

(aniline hydrochloride)

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C a (N O_{3})_{2}

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Solution

The correct option is B $C_{6} H_{12} O_{6}$ (Glucose)
$Δ T_{f} \propto m \times i$
$m =$ molality, $i =$ Van't Hoff factor
Except glucose, all other electrolytes are undergoing dissociation so $(i > 1)$ . Glucose is non electrolyte, $i = 1$ . so it has least value of $Δ T_{f}$ hence its freezing point is maximum.

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