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Doppler Effect

The frequenci...

Question

The frequencies of two sound sources are 256 Hz and 260 Hz. At t = 0, the intensity of sound is maximum. Then the phase difference at the time t = $\frac{1}{16}$ sec will be

Zero

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Solution

The correct option is C

Time interval between two comsecutive beats

T = $\frac{1}{n_{1} - n_{2}} = \frac{1}{260 - 256} = \frac{1}{4} s e c$ , $t = \frac{1}{16} = \frac{T}{4}$ sec

By using time difference = $\frac{T}{2 π} \times p h a s e$

difference $\Rightarrow \frac{T}{4} = \frac{T}{2 π} \times ϕ \Rightarrow ϕ = \frac{π}{2}$

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The frequencies of two sound sources are 256 Hz and 260 Hz. At t = 0, the intensity of sound is maximum. Then the phase difference at the time t = 116 sec will be

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