The frequency V of the radiation emitted by an atom when an electron jumps from one orbit to another is given by v - k - E- where k is a constant and - E is the change in energy level due to the transition- Then dimension of k isA- The same dimension of angular momentum-B- ML 2 T -2C- M L2 T-1D- M -1 L -2 T

If an electron in hydrogen atom jumps from an orbit of level n = 3 to an orbit of level n = 2, the emitted radiation has a frequency (R = Rydberg constant., C = velocity of light)

Q. If the electron in a hydrogen atom jumps from an orbit level

n_{1} = 3

to an orbit level

n_{2} = 2

, the emitted radiation has a wavelength given by

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The frequency ν of the radiation emitted by an atom when an electron jumps from one orbit to another is given by ν=kδE, where k is a constant and δE is the change in energy level due to the transition. Then dimension of k is

The correct option is D M−1L−2TThe dimensions of frequency are T−1 and that of energy are [M1L2T−2].Given,v=kδE ⇒T−1=k[M1L2T−2]⇒k=[M−1L−2T1]

The frequency $ν$ of the radiation emitted by an atom when an electron jumps from one orbit to another is given by $ν = k δ E$ , where k is a constant and $δ E$ is the change in energy level due to the transition. Then dimension of $k$ is

The correct option is D $M^{- 1} L^{- 2} T$
The dimensions of frequency are $T^{- 1}$ and that of energy are $[M^{1} L^{2} T^{- 2}]$ .
Given,
$v = k δ E$
$\Rightarrow T^{- 1} = k [M^{1} L^{2} T^{- 2}]$
$\Rightarrow k = [M^{- 1} L^{- 2} T^{1}]$