Given, Frequency of the man’s voice, f1=300 Hz
Wavelength of the man’s voice, λ1=1 m
Wavelength of the child’s voice, λ2=1.5 m
As we know, velocity of sound is constant for both man and child, υ=fλ
⇒f1λ1=f2λ2
(300)(1)=f2(1.5)
f2=200 Hz
Final answer: 200Hz