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Question

The frequency of a wave is 6×1015 s1. Its wave number will be:

A
105 cm1
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B
2×107 m1
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C
2×107 cm1
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D
2×105 m1
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Solution

The correct option is B 2×107 m1
We know that,
c=λv
where,
c: speed of light;
v: frequency;
λ: wavelength
Therefore,
1λ=vc
Given, frequency (v)=6×1015 s1
Hence,
wavenumber v=1λ=6×1015 s13×108 m s 1=2×107 m1

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