The frequency of fundamental tone in an open pipe of length of $0.48$ m is $320$ Hz. Speed of sound is $320$ m/sec. Frequency of fundamental tone in closed organ pipe will be

153.8

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160.0

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320.0

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140.2

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Solution

The correct option is C $160.0$ Hz
The relation between the frequency of the fundamental tone for closed and open pipe is given by:
$n_{c l o s e d} = \frac{1}{2} (n_{o p e n})$

$= \frac{1}{2} \times 320 = 160 H z$

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The frequency of fundamental tone in an open pipe of length of 0.48 m is 320 Hz. Speed of sound is 320 m/sec. Frequency of fundamental tone in closed organ pipe will be

The correct option is C 160.0 HzThe relation between the frequency of the fundamental tone for closed and open pipe is given by:nclosed=12(nopen)=12×320=160Hz

The frequency of fundamental tone in an open pipe of length of $0.48$ m is $320$ Hz. Speed of sound is $320$ m/sec. Frequency of fundamental tone in closed organ pipe will be

The correct option is C $160.0$ Hz
The relation between the frequency of the fundamental tone for closed and open pipe is given by:
$n_{c l o s e d} = \frac{1}{2} (n_{o p e n})$

$= \frac{1}{2} \times 320 = 160 H z$