The frequency of K - line of a source of atomic number Z is proportional toD- Z 2

The correct option is A (Z 1)^2 According to Moseley's law √(v) = a(Z b) ⇒ v ∝ (Z b)^2 For K_α, b = 1 So, v ∝ (Z 1)^2 and the correct choice is (b). ...

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Standard XII

Physics

Moseley's Law

The frequency...

Question

The frequency of $K_{α}$ line of a source of atomic number Z is proportional to

$Z^{2}$

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$(Z - 1)^{2}$

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$\frac{1}{Z}$

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$Z$

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Solution

The correct option is B
$(Z - 1)^{2}$

According to Moseley's law $\sqrt{v} = a (Z - b)$
$\Rightarrow v \propto (Z - b)^{2}$
For $K_{α}, b = 1$
So, $v \propto (Z - 1)^{2}$ and the correct choice is (b).

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Similar questions

The frequency of $K_{α}$ line of a source of atomic number Z is proportional to

Q. According to Moseley’s law the frequency

^{'} v^{'}

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Q. In Coolidge tube if

f

and

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represents the frequency and wavelength respectively of

K_{α}

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, then identify the option(s) which represents a straight line.

Q. When a metal of atomic number Z is used as the target in a Coolidge tube, let f be the frequency of the $K_{α}$ line. Corresponding values of Z and f are known for a number of metals. Which of the plots will give a straight line?

X -

ray from a tube with a target

A

of atomic number

Z

shows strong

K -

lines for target

A

and weak

K -

lines for impurities. The wavelength of

K_{α}

lines is

λ_{α}

for target

A

and

λ_{1}

and

λ_{2}

for two impurities.

\frac{λ_{α}}{λ_{1}} = 4 and \frac{λ_{α}}{λ_{2}} = \frac{1}{4}

Assuming the screening constant of

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The frequency of Kα line of a source of atomic number Z is proportional to

The correct option is B (Z−1)2 According to Moseley's law √v=a(Z−b) ⇒v∝(Z−b)2 For Kα, b=1 So, v∝(Z−1)2 and the correct choice is (b).

The frequency of $K_{α}$ line of a source of atomic number Z is proportional to

The correct option is B
$(Z - 1)^{2}$

According to Moseley's law $\sqrt{v} = a (Z - b)$
$\Rightarrow v \propto (Z - b)^{2}$
For $K_{α}, b = 1$
So, $v \propto (Z - 1)^{2}$ and the correct choice is (b).