Question

The Freundlich adsorption isotherm, a plot of $\log \left(x/m\right)\text{(along y-axis )}\text{and}\log P\text{(along x -axis )}$ gives a straight line. The intercept and slope for the line is $0.4771\text{and}2$ respectively. The mass of gas adsorbed per gram of adsorbent is $x\times {10}^{-4}\text{g}$. If the initial pressure is $0.04\text{atm}$. The value of $x$ is. $(\log 3=0.4771)$.

• A. 48
• B. 48.0
• C. 48.00

Answer 1

Answer: (A), (B), (C)

Frueundlich adsorption isotherm is :
$\frac{x}{m}=k{P}^{\frac{1}{n}}$
$\log \left(\frac{x}{m}\right)=\log \left(k\right)+\frac{1}{n}\log \left(P\right)$
Given
$\log \left(k\right)=0.4771=k=\log \left(3\right)$
$\Rightarrow k=3\text{and}\frac{1}{n}=2$
so,
$\frac{x}{m}=k{P}^{\frac{1}{n}}$
$\Rightarrow \frac{x}{m}=3\times (0.04{)}^2$

$\Rightarrow \frac{x}{m}=48\times {10}^{-4}$