Question

The frustum cone curved surface area is $210m^2$. The upper and lower circle area of a cone is $24$ and $15m^2$. Find the total surface area.

Answer 1

Total surface area $=\pi (R+r)s+A_1+A_2$
Curved surface area $=\pi (R+r)s=210$
$A_1=24m^2$, $A_2=15m^2$
Therefore, total surface area $=210+24+15=249m^2$