The function fx-2 x3-3 x2-90 x-174 is increasing in the intervalA- 1-2-x-1B- I-2-x-2C- 3- x -59-4D- -x-

The correct option is D ∞ lt; x lt; ∞f'(x)=6(x^2 x+15) gt; 0 ∀ x. ...

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Monotonically Increasing Functions

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Question

The function $f (x) = 2 x^{3} - 3 x^{2} + 90 x + 174$ is increasing in the interval

\frac{1}{2} < x < 1

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\frac{1}{2} < x < 2

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3 < x < \frac{59}{4}

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- \infty < x < \infty

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f (x) = 5 + 36 x + 3 x^{2} - 2 x^{3}

f (x) = 3 x^{2} + 2 x + 13

f (x) = 8 + 36 x + 3 x^{2} - 2 x^{3}

The interval in which the function $f (x) = 2 x^{3} - 3 x^{2} - 36 x + 7$ is strictly increasing is

f (x) = \frac{3}{10} x^{4} - \frac{4}{5} x^{3} - 3 x^{2} + \frac{36}{5} x + 11

f (x) = \frac{x^{4}}{4} + \frac{2}{3} x^{3} - \frac{5}{2} x^{2} - 6 x + 7

f (x) = {\{x (x - 2)\}}^{2}

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