The interval in which the function $f (x) = 2 x^{3} - 3 x^{2} - 36 x + 7$ is strictly increasing is

(-∞,2)∪(3,∞)

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(-∞,-2)∪(3,∞)

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(-2,3)

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(-3,2)

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Solution

The correct option is B
(-∞,-2)∪(3,∞)

$f^{'} (x) > 0 \Rightarrow 6 x^{2} - 6 x - 36 > 0$

$> x < - 2 o r x > 3$

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Similar questions

Find the intervals in which the function f given by f(x) = 2x³ − 3x² − 36x + 7 is

(a) strictly increasing (b) strictly decreasing

f

f (x) = 2 x^{3} - 3 x^{2} - 36 x + 7

f

f (x) = 2 x^{3} - 3 x^{2} - 36 x + 7

(a)

(b)

f (x) = 5 + 36 x + 3 x^{2} - 2 x^{3}

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