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Question

The function f:ZZ, f(x)={0 if x is oddx2 if xis even then f is

A
surjection but not injection
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B
injection but not surjection
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C
bijection
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D
neither injection nor surjection
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Solution

The correct option is A surjection but not injection
f(1)=f(3)=0; therefore f is not injection
f(2n)=n for all n.
co-domain of f=Range of f =z
f is an surjection
f is a surjection but not injection.

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