The function - y-ax-b-x-1-x-4- nbsp- has turning point at - P-2-1- nbsp- Then find the value of - a- and - b-

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Stationary Point

The function ...

Question

The function $y = \frac{a x + b}{(x - 1) (x - 4)}$ has turning point at $P (2, - 1)$ . Then find the value of $a$ and $b$ .

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y = \frac{a x + b}{(x - 1) (x - 4)}

(2, - 1)

a

b

y = \frac{ax + b}{(x - 1) (x - 4)}

y = \frac{ax + b}{(x - 1) (x - 4)}

f (x) = \frac{a x + b}{(x - 1) (x - 4)}

(2. - 1)

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