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Question

The function y specified implicitly by the relation y0et dt+x0cost dt=0 satisfies the differential equation :

A
ey(d2ydx2+(dydx)2)=sinx
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B
e2y(d2ydx2+(dydx)2)=sinx
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C
ey(d2ydx2+(dydx)2)=sin2x
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D
ey(2d2ydx2+(dydx)2)=sinx
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Solution

The correct option is A ey(d2ydx2+(dydx)2)=sinx
Using Newton Leibnitz rule, we get
eydydx+cosx=0eyd2ydx2+ey(dydx)2sinx=0
ey(d2ydx2+(dydx)2)=sinx

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