The fundamental frequency of an open organ pipe at 15oC is 156 Hz. At what temperature, will the fundamental frequency be 160Hz? neglect expansion of tube .
Open in App
Solution
We know that for open organ pipe first resonance occurs when l=λ2 or λ=2l
Hence 156=v152l 160=vt2l
Also we know that velocity of sound vT∝T ∴v15vt=156160=√273+15273+t ∴288273+t=3940×3940: 273+t=288×40×4039×39=32×40×40169=51200169=303 ∴t=303−273=30oC
Why this question?
Caution: While using the expression that velocity of sound at any temperature T, vT∝T, remember to take temperature T in kelvin scale.