The fundamental frequency of an open pipe is 30 Hz. If one end of the pipe is closed, then the fundamental frequency will be

15 Hz

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30 Hz

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45 Hz

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60 Hz

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Solution

The correct option is B 15 Hz
For closed organ pipe, frequency of the fundamental note
$ν_{0 c} = \frac{v}{4 l}$ , where v is velocity of sound and l is the length of the pipe.
For open organ pipe, frequency of the fundamental note
$ν_{0 o} = \frac{v}{2 l} = 2 ν_{0 c}$
$ν_{0 c} = \frac{1}{2} ν_{0 o} = \frac{30}{2} = 15 Hz$

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The fundamental frequency of an open pipe is 30 Hz. If one end of the pipe is closed, then the fundamental frequency will be

The correct option is B 15 HzFor closed organ pipe, frequency of the fundamental noteν0c=v4l, where v is velocity of sound and l is the length of the pipe.For open organ pipe, frequency of the fundamental noteν0o=v2l=2ν0cν0c=12ν0o=302=15 Hz