Question

The gas having the same number of molecules as $16$g of oxygen is:

• A. $16$g of $O_3$
• B. $16$g of $S{O}_3$
• C. $48$g of $S{O}_3$
• D. $1$g of $H_2$

Answer 1

Answer: (D)

$1$g of $H_2$

$16$g of oxygen gas is $0.5$ mole of it and has $0.5$ $N_A$ molecules.

$16$g of ozone is $\frac{1}{3}$ moles and thus, has $\frac{1}{3}\times N_A$ molecules
$16$g of $S{O}_3$ is $\frac{1}{5}$ moles and thus, has $\frac{1}{5}\times N_A$ molecules
$48$g of $S{O}_3$ is $\frac{3}{5}$ moles and thus, has $\frac{3}{5}\times N_A$ molecules
$1$g of hydrogen is $0.5$ moles of hydrogen gas and has $0.5\times N_A$ molecules

Hence, option D is correct.